SOLUTION: Calculate the term independent of x in the binomial expansion of (x-1/2x^5)^18

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Question 1073361: Calculate the term independent of x in the binomial expansion of (x-1/2x^5)^18
Found 2 solutions by KMST, MathTherapy:
Answer by KMST(5328) About Me  (Show Source):
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The expansion of %28x-1%2F2x%5E5%29%5E18=%28x%2B%28-1%2F2%29x%5E%28-5%29%29%5E18
has terms of the form
.
The term independent of x is the one with
18-6n=0<-->18=6n<-->18%2F6=n<-->n=3
So, that term independent of x is
%28matrix%282%2C1%2C18%2Cn%29%29=18%2A17%2A16%2F%282%2A3%29=highlight%28816%29

Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!

Calculate the term independent of x in the binomial expansion of (x-1/2x^5)^18
The term that's independent of x is the constant in the expansion, and is the 4th term of the expansion, which is: highlight_green%28-+102%29