SOLUTION: Find two consecutive even integers such that twice the smaller is 16 more than the larger.

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Question 1073195: Find two consecutive even integers such that twice the smaller is 16 more than the larger.
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
Let n be the smaller integer. Then the larger integer is n+2. So:
2n=n+2+16
n=18
The smaller integer is 18; the larger one is 20. ☺☺☺☺