SOLUTION: For three weeks in December your boss holds a lottery to receive an extra day off for the holidays. You and 9 other employees are entered each week and one name is chosen at rando
Algebra ->
Probability-and-statistics
-> SOLUTION: For three weeks in December your boss holds a lottery to receive an extra day off for the holidays. You and 9 other employees are entered each week and one name is chosen at rando
Log On
Question 1072906: For three weeks in December your boss holds a lottery to receive an extra day off for the holidays. You and 9 other employees are entered each week and one name is chosen at random (you can win more than once). What is the probability that you win at least one time? Answer by jorel1380(3719) (Show Source):
You can put this solution on YOUR website! Let's look at the possibility of NOT being chosen. That would be (8/9)^3, since the lottery is being held for three weeks. This amounts to 0.702331961591220850480109739369. Now we take this and subtract it from 1, which gives us 0.297668038408779149519890260631, or a 29.7668% chance of being picked at least once. ☺☺☺☺
