SOLUTION: consider the linear equation 2x-3y=-3. if (-3,y1) is a point on the graph of the line, find the missing coordinate. y1=? And if (x2,1) is a point on the graph of the line, find the

Algebra ->  Linear-equations -> SOLUTION: consider the linear equation 2x-3y=-3. if (-3,y1) is a point on the graph of the line, find the missing coordinate. y1=? And if (x2,1) is a point on the graph of the line, find the      Log On


   

Question 1072727: consider the linear equation 2x-3y=-3. if (-3,y1) is a point on the graph of the line, find the missing coordinate. y1=? And if (x2,1) is a point on the graph of the line, find the missing coordinate. x2=?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
2x-3y=-3
If x=-3, find y.
(Meaning, what is y%5B1%5D ?)

-3y=-2%2A%28-3%29-3
-3y=3
highlight%28y%5B1%5D=-1%29


The other unknown point works similarly.

Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!
consider the linear equation 2x-3y=-3. if (-3,y1) is a point on the graph of the line, find the missing coordinate. y1=? And if (x2,1) is a point on the graph of the line, find the missing coordinate. x2=?
2x - 3y = - 3
Substitute - 3 for x and find y, which is the same as: y%5B1%5D
highlight_green%28matrix%281%2C5%2C+y%2C+or%2C+y%5B1%5D%2C+%22=%22%2C+-+1%29%29
Apply the same concept for the 2nd part, and you should be able to find x, which is the same as: x%5B2%5D.