SOLUTION: Find three consecutive odd positive integers such that five times the sum of all three is 72 more than the product of the first and second integers .

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Question 1072634: Find three consecutive odd positive integers such that five times the sum of all three is 72 more than the product of the first and second integers .
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
The integers, system%28x-2%2Cx%2Cx%2B2%29

5%28x-2%2Bx%2Bx%2B2%29=72%2B%28x%28x-2%29%29


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5%283x%29=x%5E2-2x%2B72
x%5E2-17x%2B72=0
Discriminant, 289-4%2A72=1,.... or,

%28x%5E2-17x%2B72%29=highlight_green%28%28x-8%29%28x-9%29=0%29
and the description specified ODD integers.
x=9


The consecutive odd positive integers: 7, 9, 11