SOLUTION: The perimeter of a rectangle is 44 inches. If the length is increased by twice the width, the result is 31 inches. Find the length and width of the rectangle. x+y=44 and 2x+y=31?

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: The perimeter of a rectangle is 44 inches. If the length is increased by twice the width, the result is 31 inches. Find the length and width of the rectangle. x+y=44 and 2x+y=31?      Log On

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Question 1072614: The perimeter of a rectangle is 44 inches. If the length is increased by twice the width, the result is 31 inches. Find the length and width of the rectangle.
x+y=44 and 2x+y=31?
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
44 to 31 is not an increase. Recheck the problem description.