SOLUTION: 1)Solve for X log(Square root of 5)(x) =6 -I am not sure how to put in a square root sign. but the square root of 5 is the base. 2)log(3)x+1+log(3)(x+6)=2 3 is the base in

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: 1)Solve for X log(Square root of 5)(x) =6 -I am not sure how to put in a square root sign. but the square root of 5 is the base. 2)log(3)x+1+log(3)(x+6)=2 3 is the base in       Log On


   

Question 1072598: 1)Solve for X
log(Square root of 5)(x) =6
-I am not sure how to put in a square root sign. but the square root of 5 is the base.

2)log(3)x+1+log(3)(x+6)=2
3 is the base in this question on both sides.

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
1:

log(sqrt(5),x)=6
log%28sqrt%285%29%2Cx%29=6

%28sqrt%285%29%29%5E6=x

x=%285%5E%281%2F2%29%29%5E6

x=5%5E%286%2F2%29

x=5%5E3

x=125



2:
log%283%2Cx%29%2B1%2Blog%283%2C%28x%2B6%29%29=2

log%283%2Cx%29%2Blog%283%2C%28x%2B6%29%29=2-1=1

log%283%2C%28x%28x%2B6%29%29%29=1

Exponential Form: 3%5E1=x%28x%2B6%29

x%28x%2B6%29=3, and you can do the rest.