SOLUTION: F(x)=.5(2^x), G(x)=5x-12 A) Determine g(f(0) I did try this question and got -9.5 is this incorrect? B)(f*g)(x) I got to 5(2^(5x-12)) I didn't know what to do with the upper

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: F(x)=.5(2^x), G(x)=5x-12 A) Determine g(f(0) I did try this question and got -9.5 is this incorrect? B)(f*g)(x) I got to 5(2^(5x-12)) I didn't know what to do with the upper      Log On


   

Question 1072597: F(x)=.5(2^x), G(x)=5x-12
A) Determine g(f(0)
I did try this question and got -9.5 is this incorrect?
B)(f*g)(x)
I got to 5(2^(5x-12)) I didn't know what to do with the upper numbers.
h.) Determine f^(-1)(x)
(-1) is the power and (x) is on the side.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
g%28f%29=5f-12=5%280.5%2A2%5E%28x%29%29-12=2%5E%28x%29-12
So then,
g%28f%280%29%29=2%5E%280%29-12=1-12=-11
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f%28g%29=0.5%282%5E%285x-12%29%29
Yes, correct.
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.
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Use x,y nomenclature.
Substitute x and y and solve for the new y.
y=0.5%282%5Ex%29
x=0.5%282%5Ey%29
2x=2%5Ey
y=log%28%282x%29%29%2Flog%28%282%29%29
f%5E%28-1%29%28x%29=log%28%282x%29%29%2Flog%28%282%29%29