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| Question 1072350:  Solve sin 4x = cos 2x
 Found 2 solutions by  Boreal, ikleyn:
 Answer by Boreal(15235)
      (Show Source): 
You can put this solution on YOUR website! sin 4x=2 sin 2x*cos 2x That equals cos 2x
 divide by cos 2x
 2 sin 2x=1
 sin 2x=(1/2)
 x=pi/12
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 check
 sin pi/3 should equal cos pi/6
 This is true.
 
Answer by ikleyn(52879)
      (Show Source): 
You can put this solution on YOUR website! . 
 
sin(4x) = cos(2x)  --->  2sin(2x)*cos(2x) = cos(2x)  --->  2sin(2x)*cos(2x) - cos(2x)  = 0  --->  
cos(2x)*(2sin(2x)-1) = 0.
The last equation deploys in two independent equations:
1.  cos(2x) = 0  ---->  x =  , x =  ,  x =  and  x =  2.  2sin(2x)-1 = 0  ---->  sin(2x) =  ,  which implies 
    2x =  and/or   2x =  .
    This, in turn, implies that the original equation has 4 (four) solutions in the interval 0 <= x <  :
    x =  ,  x =  ,  x =  and  x =  .
Answer.  In all, there are 8 solutions:  x =  , x =  ,  x =  ,  x =  ;    x =  ,  x =  ,  x =  ,  x =  . Solved.
 
 
 
   
 Plots y = sin(4x) (red) and y = cos(2x) (green)
 
 
 To see more examples of solved trigonometry equations with detailed solutions, look into the lessons
 - Solving simple problems on trigonometric equations
 - Solving typical problems on trigonometric equations
 - Solving more complicated problems on trigonometric equations
 - Solving advanced problems on trigonometric equations
 - OVERVIEW of lessons on calculating trig functions and solving trig equations
 in this site.
 
 
 Also, you have this free of charge online textbook in ALGEBRA-II in this site
 - ALGEBRA-II - YOUR ONLINE TEXTBOOK.
 
 The referred lessons are the part of this online textbook under the topic "Trigonometry: Solved problems".
 
 
 The solution by "Boreal" is wrong, since it does not cover a lot of roots.
 
 
 
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