Question 1072295: Thank you for your support. I am sending this email from Nigeria.
I have a question on my table for quite sometime now and i will love for you to assist me in solving the question
1. The number of students in a class is 9. There are three(3) classes.
Class A = 11, 22, YY, 1Y, 2Y, Y1, Y2, 12, 11.
Class B = 11, 22, YY, 1Y, 2Y, Y1, Y2, 12, 11.
Class C = 11, 22, YY, 1Y, 2Y, Y1, Y2, 12, 11.
Whats the possible outcome of picking 1 student at a time from each class, to make 3 student per pick.
i.e (11,22,YY) (11,22,12) (11,Y1,Y2)
2. State the method how each possible outcome could be picked.
Answer by Fombitz(32388)   (Show Source):
You can put this solution on YOUR website! So from each class you have nine choices so for the 3 class pick you'd have,
 possible picks.
.
.
Why do you have two 11's for each class.
I'll treat them as separate students but you should change the name to avoid confusion.
Start with Class A, first choice 11A
(11A, CB, CC)
Choose Class B, first choice 11B
(11A, 11B, CC)
Then choose each possible choice in Class C,
(11A,11B,11C)
(11A,11B,22C)
(11A,11B,YYC)
(11A,11B,1YC)
(11A,11B,2YC)
(11A,11B,Y1C)
(11A,11B,Y2C)
(11A,11B,12C)
(11A,11B,11C)
Then move to the next Class B choice, 22B.
(11A,22B,11C)
(11A,22B,22C)
(11A,22B,YYC)
(11A,22B,1YC)
(11A,22B,2YC)
(11A,22B,Y1C)
(11A,22B,Y2C)
(11A,22B,12C)
(11A,22B,11C)
Once you exhaust all the B choices then increment on A and start all over again,
As an example,
(22A,11B,11C)
(22A,11B,22C)
(22A,11B,YYC)
(22A,11B,1YC)
(22A,11B,2YC)
(22A,11B,Y1C)
(22A,11B,Y2C)
(22A,11B,12C)
(22A,11B,11C)
Keep going this way until you have 729 picks made.
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