SOLUTION: Please help me solve this problem .
A 2000-L tank is initially filled with a copper sulfate solution with a concentration of 60g/L . A copper sulfate solution with a concentration
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: Please help me solve this problem .
A 2000-L tank is initially filled with a copper sulfate solution with a concentration of 60g/L . A copper sulfate solution with a concentration
Log On
Question 1072004: Please help me solve this problem .
A 2000-L tank is initially filled with a copper sulfate solution with a concentration of 60g/L . A copper sulfate solution with a concentration of 20g/L flows into the tank at rate of 8L/min . The thoroughly mixed solution is drained from the tank at rate 8L/min .
A)write an initial value problem for the mass of the copper sulfate .
B)Solve the initial value problem . Set up .
This is how i solved it but i might be 90% wrong .Please feel free to correct anything i did wrong .
Let y(t) be the amount of sulfate .
y(0)=60
dy/dt=(rate in)-(rate out)
rate in =(20g/L)(8L/min)=160g/min
rate out =y(t)g/2000L)(8L/min)=y(t)g/250min
dy/dt=160-(y(t)/250)
dy/dt=(40000-y(t))/250
taking integral both side
int(dy/40000-y)=int(dt/250)
-ln(40000-y)=t/250+c
since y(0)=60 , we have -ln39940=c
-ln(40000-y)=t/250-ln39940
since y(t)is continuous and y(0)=60 , so 40000-y(t) is positive . Thus 40000-y=40000-y
y(t) 40000-39940e^(-t/250).
*Please any help will be very appreciate . Thank
