SOLUTION: Convert to trigonometric form: {{{ z = 4 }}} square root of 3 space plus space 4 i A.) 8(cos60 + i sin60) B.) 8(cos30 + i sin30) C.) 8(sin30 + i cos30) D.) 8(sin60 + i cos60

Algebra ->  Test -> SOLUTION: Convert to trigonometric form: {{{ z = 4 }}} square root of 3 space plus space 4 i A.) 8(cos60 + i sin60) B.) 8(cos30 + i sin30) C.) 8(sin30 + i cos30) D.) 8(sin60 + i cos60      Log On


   



Question 1071888: Convert to trigonometric form: +z+=+4+ square root of 3 space plus space 4 i
A.) 8(cos60 + i sin60)
B.) 8(cos30 + i sin30)
C.) 8(sin30 + i cos30)
D.) 8(sin60 + i cos60)

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
4sqrt%283%29%2B4i=8%28sqrt%283%29%2F2%2BI%281%2F2%29%29
cos%2830%5Eo%29=sqrt%283%29%2F2 and sin%2830%5Eo%29=1%2F2 , so
4sqrt%283%29%2B4i=8%28cos%2830%5Eo%29%2Bi%2Asin%2830%5Eo%29%29

TIP:
If they give you a complex number with
a non-zero real part, and
a different non-zero imaginary part,
and the angle has to be a nice round number,
one part will be sqrt%283%29 or -sqrt%283%29
times the other part,
Because the only exact angles with
non-zero, different, and simple-to-write
cosine and sine are 30%5Eo , 60%5Eo in quadrant 1,
and angles symmetrical to those in the other quadrants.
cos%2830%5Eo%29=sqrt%283%29%2F2=sin%2860%5Eo%29 and
cos%2860%5Eo%29=1%2F2=sin%2830%5Eo%29 .
If both parts are positive, it is one of those angles.
If there are negative parts,
it is a symmetrical angle on another quadrant.
For example, -1%2Bsqrt%283%29%2Ai
has a negative real part, and a positive imaginary part,
so it would be plotted in quadrant 2.
The real part has to be cosine times something,
so it is %281%2F2%29%28-2%29=-1
The quadrant 1 angle with 1%2F2 for a cosine
is 60%5Eo .
To get the symmetrical angle from quadrant 2,
You subtract from 180%5Eo ,
to get 180%5Eo-60%5Eo=120%5Eo in quadrant 2.
So,
.
If both parts are negative,
the complex number would be plotted in quadrant 3,
where the angle would be 180%5Eo plus
the symmetrical reference angle from quadrant 1.
If the real part is positive,
and the imaginary part negative,
You are in quadrant 4,
and the angle is 360%5Eo minus
the quadrant 1 angle.

FORMULAS:
Any complex number,
a+%2B+i+b ,
with a , and b being real numbers,
can always be written as
r+%28cos%28theta%29+%2B+i+sin%28theta%29%29
The formulas for r and theta are:
r+=+sqrt+%28a%5E2+%2B+b%5E2%29
cos%28theta%29+=+a%2Fr
and
sin%28theta%29++=+b%2Fr .
The last 2 formulas allow you to find theta
(in degrees or radians) with any scientific calculator.
If the calculator gives you a negative angle, add 360%5Eo (or 2pi when working in radians).
(For faster calculations, you can use
tan%28theta%29+=+b%2Fa and the signs, positive or negative, of a and b ).