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4x+10y = 48 (1)
10x+4y = 36 (2)
Multiply both sides of (1) by 10, and both sides of (2) by 4:
40x + 100y = 480 (1')
40x + 16y = 144 (2')
Subtract (2') from (1') to get:
0x + 84y = 336 —> y = 336/84 = 4.
Using 4x + 10y = 48 and y=4 —> 4x + 10(4) = 48 —> 4x = 48-40 —> 4x = 8 —> x=2
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Ans:
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Check: 4(2) + 10(4) = 8 + 40 = 48 (ok, eqn 1 works)
10(2) + 4(4) = 20 + 16 = 36 (ok, eqn 2 works as well)
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