Question 1071569: The length of the rectangle (8g-5) meters and the width of the rectangle is (2g+4) meters. If the area of the rectangle is 585 square meters, find the value of g as it relates to this rectangle, the numerical value of the length, and the numerical value of the width.
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! The length of the rectangle (8g-5) meters and the width of the rectangle is (2g+4) meters.
If the area of the rectangle is 585 square meters, find the value of g as it relates to this rectangle,
L*W = 585
therefore
(8g-5)*(2g+4) = 585
FOIL
16g^2 + 32g - 10g - 20 - 585 = 0
A quadratic equation
16g^2 + 22g - 605 = 0
Use the quadratic formula.a=16; b=22; c=-605
Positive solution
g = 5.5
:
Find the numerical value of the length, and the numerical value of the width.
L: 8(5.5) - 5 = 39 is the length
W: 2(5.5) + 4 = 15 is the width
:
:
See if that checks, find the area.
39 * 15 = 585
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