SOLUTION: A man has a rectangular garden. One length of the garden lies along a patio wall. However, the rest of the garden is enclosed by 28 feet of fencing. If the length of the garden is

Algebra ->  Finance -> SOLUTION: A man has a rectangular garden. One length of the garden lies along a patio wall. However, the rest of the garden is enclosed by 28 feet of fencing. If the length of the garden is       Log On


   



Question 1071441: A man has a rectangular garden. One length of the garden lies along a patio wall. However, the rest of the garden is enclosed by 28 feet of fencing. If the length of the garden is twice its width what is the area of the garden?
Answer by ikleyn(53765) About Me  (Show Source):
You can put this solution on YOUR website!
.

    x + y + x = 28,
    y = 2x.

    ---->  4y = 28  --->  y = 28%2F4 ft = 7 ft.

    ---->  x = 2*7 = 14 ft.

    The area = 7*14 ft^2 = 98 ft^2.