SOLUTION: four teams play a game.their probability of winning the game are 1/8 ,1/7,1/9 and 1/10 respectively find the probability of any of the team winning also find the probability that n
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Question 1071399: four teams play a game.their probability of winning the game are 1/8 ,1/7,1/9 and 1/10 respectively find the probability of any of the team winning also find the probability that no team may win Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Four teams play a game.their probability of winning the game are 1/8 ,1/7,1/9 and 1/10 respectively find the probability of any of the team winning also find the probability that no team may win.
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Prob one of them wins = (1/8)+(1/7)+(1/9)+(1/10) = 1207/2520
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Prob none of them win = 1-(7/8)(6/7)(8/9) = 1/3
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Cheers,
Stan H.
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