Question 1071327: State the excluded values for the following expression. Then simplify the expression.
v^2-6v-40/v^2+5v+4 Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! The values excluded is where the denominator equals 0.
v^2+5v+4=0
(v+4)(v+1)=0
v=-1,-4; those are the excluded values for v.
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The numerator factors into (v-10)(v+4)
When divided by the den. (v+1)(v+4)
The (v+4) cancel
The simplified expression is (v-10)/(v+1), for v NE to -1 or -4.
