SOLUTION: solve using augmented matrices 6r+s=9 3r+2s=0

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Question 107130This question is from textbook Algebra 2 with trigonometry
: solve using augmented matrices
6r+s=9
3r+2s=0 This question is from textbook Algebra 2 with trigonometry

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Start with the system

6r+s=9
3r+2s=0

Now form an augmented matrix


%28matrix%282%2C3%2C6%2C1%2C9%2C3%2C2%2C0%29%29

Multiply Row 1 by 1%2F6 to make the pivot 1:

%28matrix%282%2C3%2C1%2C1%2F6%2C3%2F2%2C3%2C2%2C0%29%29

Add -3*Row 1 to Row 2 to get the new Row 2

%28matrix%282%2C3%2C1%2C1%2F6%2C3%2F2%2C0%2C3%2F2%2C-9%2F2%29%29

Multiply Row 2 by 2%2F3 to make the pivot 1:

%28matrix%282%2C3%2C1%2C1%2F6%2C3%2F2%2C0%2C1%2C-3%29%29



Add -1/6*Row 2 to Row 1 to get the new Row 1

%28matrix%282%2C3%2C1%2C0%2C2%2C0%2C1%2C-3%29%29


The matrix is now in reduced row echelon form

So the answer is
r=2 and s=-3