SOLUTION: Given: {{{sin(theta)-cos(theta)=1/2}}} Prove: {{{sin(theta)+cos(theta)=("" +- sqrt(7))/2}}}

Algebra ->  Trigonometry-basics -> SOLUTION: Given: {{{sin(theta)-cos(theta)=1/2}}} Prove: {{{sin(theta)+cos(theta)=("" +- sqrt(7))/2}}}      Log On


   



Question 1071242: Given: sin%28theta%29-cos%28theta%29=1%2F2
Prove: sin%28theta%29%2Bcos%28theta%29=%28%22%22+%2B-+sqrt%287%29%29%2F2

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
sin%28theta%29-cos%28theta%29=1%2F2

Square both sides

sin%28theta%29%5E2-2sin%28theta%29cos%28theta%29%2Bcos%5E2%28theta%29=1%2F4

sin%28theta%29%5E2%2Bcos%5E2%28theta%29-2sin%28theta%29cos%28theta%29=1%2F4

1-2sin%28theta%29cos%28theta%29=1%2F4

1-sin%282theta%29=1%2F4

-sin%282theta%29=-3%2F4

sin%282theta%29=3%2F4

cos%282theta%29=+%22%22+%2B-+sqrt%281-sin%5E2%282theta%29%29

cos%282theta%29=+%22%22+%2B-+sqrt%281-%283%2F4%29%5E2%29

cos%282theta%29=+%22%22+%2B-+sqrt%281-9%2F16%29

cos%282theta%29=+%22%22+%2B-+sqrt%2816%2F16-9%2F16%29

cos%282theta%29=+%22%22+%2B-+sqrt%287%2F16%29

cos%282theta%29=+%22%22+%2B-+sqrt%287%29%2F4

cos%282theta%29=cos%5E2%28theta%29-sin%5E2%28theta%29

sin%5E2%28theta%29-cos%5E2%28theta%29=-cos%282theta%29



%281%2F2%29%28sin%28theta%29%2Bcos%28theta%29%5E%22%22%29=%28%22%22+%2B-+sqrt%287%29%29%2F4

sin%28theta%29%2Bcos%28theta%29=%28%22%22+%2B-+sqrt%287%29%29%2F2

That's the proof.

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Notice that the right side could be either positive or negative,
although you did not have the ± originally.  I included it above).

To show that it can  be either positive or negative:

By calculator the solutions between 0° and 360° are approximately

theta=%2265.70481105%B0%22 and theta=%22204.2951889%B0%22

and sqrt%287%29%2F2=1.322874656

For theta=%2265.70481105%B0%22

sin%2865.70481105%29%2Bcos%2865.70481105%29=+1.322875656

and for theta=%22204.2951889%B0%22,

sin%28%22204.2951889%B0%22%29%2Bcos%28%22204.2951889%B0%22%29=+-1.322875656

So you see that it can be positive or negative.

Edwin