SOLUTION: I have 2 questions: what if Pascal wanted the area of the floor to be 54 square feet and the width still to be 2/3 in length? What would the dimensions of the floor be? Leo wan

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: I have 2 questions: what if Pascal wanted the area of the floor to be 54 square feet and the width still to be 2/3 in length? What would the dimensions of the floor be? Leo wan      Log On


   

Question 1071170: I have 2 questions: what if Pascal wanted the area of the floor to be 54 square feet and the width still to be 2/3 in length? What would the dimensions of the floor be?
Leo wants to paint a mural that covers a wall with an area of 1,440sq feet. The height of the wall is 2/5 of it's length. What is the length and the height of the wall?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
(1)
I read this as:
The width is 2/3 of the length
If that is correct, then
Let +x+ = the length of the floor
+%282%2F3%29%2Ax+ = the width of the floor
----------------------------------
+x%2A%282%2F3%29%2Ax+=+54+
+%282%2F3%29%2Ax%5E2+=+54+
+x%5E2+=+%283%2F2%29%2A54+
+x%5E2+=+81+
+x+=+9+
and
+%282%2F3%29%2Ax+=+%282%2F3%29%2A9+
+%282%2F3%29%2Ax+=+6+
The dimensions are 6 x 9
check:
+6%2A9+=+54+
OK
--------------------------
(2)
Let +x+ = the length of the wall
+%282%2F5%29%2Ax+ = the height of the wall
----------------------------------
+x%2A%282%2F5%29%2Ax+=+1440+
+%282%2F5%29%2Ax%5E2+=+1440+
+x%5E2+=+%285%2F2%29%2A1440+
+x%5E2+=+3600+
+x+=+60+
and
+%282%2F5%29%2Ax+=+%282%2F5%29%2A60+
+%282%2F5%29%2Ax+=+24+
The dimensions are 24 x 60
----------------------------
check:
+24%2A60+=+1440+
OK