Question 1071139: Any help is greatly appreciated. totally lost on this one:
Let L_1={1,2,4,5,5,7}. The average of the list L_1 is 4 and its standard deviation is 2.
a)Let c>0 be a real number and L_2={1+c,2+c,4+c,5+c,5+c,7+c}.
Note that L_2 is obtained by adding the constant c to each element of L_1. Find the average and the standard deviation of the list L_2. Explain your answers.
b) Let c>0 be a real number and L_3={1*c,2*c,4*c,5*c,5*c,7*c}.
Note that L_3 is obtained by multiplying the constant c to each element of L_1. Find the average and the standard deviation of the list L_3. Explain your answers.
Answer by rothauserc(4718)   (Show Source):
You can put this solution on YOUR website! a) average for L_2 = (1+c+2+c+4+c+5+c+5+c+7+c) / 6 = (24 + 6c) / 6 = 4 + c
standard deviation(s) for L_2 = square root( (1/6) * summation of i from 1 to 6 (x(i)+c - (4+c))^2)
s = square root( (1/6) * summation of i from 1 to 6 (x(i) - 4)^2) = 2
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b) average for L_3 = {1*c+2*c+4*c+5*c+5*c+7*c} / 6 = (c*24) / 6 = 4c
s = square root( (1/6) * summation of i from 1 to 6 (x(i)c - (4c))^2) = 2 * square root(c)
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