SOLUTION: The widths of two similar rectangles have a ratio of 2:6
The area of the smaller rectangle is 12 ft2.
What is the area of the larger rectangle?
I'm not sure how to go abou
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The area of the smaller rectangle is 12 ft2.
What is the area of the larger rectangle?
I'm not sure how to go abou
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Question 1071110: The widths of two similar rectangles have a ratio of 2:6
The area of the smaller rectangle is 12 ft2.
What is the area of the larger rectangle?
I'm not sure how to go about this question. How do you solve it? Found 2 solutions by addingup, MathTherapy:Answer by addingup(3677) (Show Source):
You can put this solution on YOUR website! ratio 2:6, the smaller is 12 so this is the 2 in the ratio.
2 = 12
6 = x
cross multiply:
2x = 72
x = 36
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Check:
2+6 = 8
2/8 = 0.25
6/8 = 0.75
Now with the areas:
12+36 = 48
12/48 = 0.25
36/48 = 0.75 Correct.
You can put this solution on YOUR website!
The widths of two similar rectangles have a ratio of 2:6
The area of the smaller rectangle is 12 ft2.
What is the area of the larger rectangle?
I'm not sure how to go about this question. How do you solve it?
The rectangles' sides are in a ratio of (smaller to larger), and so, their areas will be in a ratio of 12:32, or 1:9.
Now, since the smaller rectangle's area is 12 ft2, it follows that the larger rectangle's area will be:
