SOLUTION: solve cos(theta)+sin(theta)=0 over the interval (0,2pi)

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Question 1070737: solve cos(theta)+sin(theta)=0 over the interval (0,2pi)
Answer by Alan3354(69443) About Me  (Show Source):
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solve cos(theta)+sin(theta)=0 over the interval (0,2pi)
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Cos = -sin
cos^2 = sin^2
1-sin^2 = sin^2
2sin^2 = 1
sin = ħsqrt(1/2) in the quadrants where sine and cosine are opposite signs.
theta = 3pi/4, 7pi/4