SOLUTION: 1) Find the​ z-score such that the area under the standard normal curve to the left is 0.86 2)Find the​ z-scores that separate the middle 83​% of the distribu

Algebra ->  Probability-and-statistics -> SOLUTION: 1) Find the​ z-score such that the area under the standard normal curve to the left is 0.86 2)Find the​ z-scores that separate the middle 83​% of the distribu      Log On


   



Question 1070681: 1) Find the​ z-score such that the area under the standard normal curve to the left is 0.86
2)Find the​ z-scores that separate the middle 83​% of the distribution from the area in the tails of the standard normal distribution.

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Using EXCEL's NORMSINV,
z=1.080
.
.
.
Using symmetry,
1-0.83=0.17
Half goes to the right hand side and half goes to the left.
So find z such that z=0.17%2F2=0.085
Using EXCEL's NORMSINV,
z%5B1%5D=-1.3722
Using symmetry,
z%5B2%5D=1.3722