SOLUTION: how do you solve 3\2x+1 + 3\ 2x-1= 8x\4x^2-1?

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Question 107053: how do you solve 3\2x+1 + 3\ 2x-1= 8x\4x^2-1?
Answer by HyperBrain(694) About Me  (Show Source):
You can put this solution on YOUR website!
%283%29%2F%282x%2B1%29+%2B+%283%29%2F+%282x-1%29=+%288x%29%2F%284x%5E2-1%29
First I will introduce a special product first-----the difference of two squares.

It states that
a%5E2-b%5E2=%28a%2Bb%29%28a-b%29

We can apply this here to make this problem easy to solve.

%283%29%2F%282x%2B1%29+%2B+%283%29%2F+%282x-1%29=+%288x%29%2F%284x%5E2-1%29
%283%29%2F%282x%2B1%29+%2B+%283%29%2F+%282x-1%29=+%288x%29%2F%28%282x%29%5E2-1%5E2%29
%283%29%2F%282x%2B1%29+%2B+%283%29%2F+%282x-1%29=+%288x%29%2F%28%282x%2B1%29%282x-1%29%29

3%282x%2B1%29%2B3%282x-1%29+=8x
%286x%2B3%29%2B%286x-3%29=8x
%286x%2B6x%29%2B%283-3%29=8x
12x%2B0=8x
12x=8x
12x-8x=8x-8x
4x=0
4x%2F4=0%2F4
x=0


Power up,
HyperBrain!