SOLUTION: Write the slope-intercept form of an equation that passes through (-7,-13) and is perpendicular to the graph of y=-1/5x+5

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: Write the slope-intercept form of an equation that passes through (-7,-13) and is perpendicular to the graph of y=-1/5x+5      Log On


   

Question 1070451: Write the slope-intercept form of an equation that passes through (-7,-13) and is perpendicular to the graph of y=-1/5x+5
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+y+=+%28-1%2F5%29%2Ax+%2B+5+
+m+=+-1%2F5+
Any line perpendicular to this one will
have slope = +-1%2Fm+
+-1%2F%28-1%2F5%29+=+5+
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Use general point-slope formula
+%28+y+-%28-13%29+%29+%2F+%28+x+-+%28-7%29+%29+=+5+
+%28+y+%2B+13+%29+%2F+%28+x+%2B+7+%29+=+5+
+y+%2B+13+=+5%2A%28+x+%2B+7+%29+
+y+%2B+13+=+5x+%2B+35+
+y+=+5x+%2B+22+
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check answer:
( -7, -13 )
+y+=+5x+%2B+22+
+-13+=+5%2A%28-7%29+%2B+22+
+-13+=+-35+%2B+22+
+-13+=+-13+
OK