Question 1070354: What's the center of gravity of the system given of; m1=2250 kg, x1=2,5 m, y1= 2 m, z1= 1,5 m, m2=2750 kg, x2=1,5 m, y2= -1,5 m, z2= 1 m, m3=3250 kg, x3=-2 m, y3= 3 m, z3= 4 m and m4=2500 kg, x4=1,5 m, y4= 1,5 m, z4= 2,5
Answer by rothauserc(4718)   (Show Source):
You can put this solution on YOUR website! Center of mass and center of gravity are used to mean the same thing
:
The center of mass(cm) for the system has three coordinates
:
x(cm), y(cm), z(cm)
:
x(cm) = (summation using i from 1 to N of m(i)x(i)) / M, where N = 4 and M is the total mass
:
y(cm) = (summation using i from 1 to N of m(i)y(i)) / M, where N = 4 and M is the total mass
:
z(cm) = (summation using i from 1 to N of m(i)z(i)) / M, where N = 4 and M is the total mass
:
M = 2250 + 2750 + 3250 + 2500 = 10750
:
*************************************
x(cm) = 7000 / 10750 = 0,6512m
:
y(cm) = 13875 / 10750 = 1,2907m
:
z(cm) = 25375 / 10750 = 2,3605
*************************************
:
|
|
|
