SOLUTION: 13. In the 2016 U.S. election, 47% of the votes were for Don-
ald Trump, 48% of the votes were for Hilary Clinton, and the
remaining 5% were for other candidates. Suppose we take
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-> SOLUTION: 13. In the 2016 U.S. election, 47% of the votes were for Don-
ald Trump, 48% of the votes were for Hilary Clinton, and the
remaining 5% were for other candidates. Suppose we take
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Question 1070258: 13. In the 2016 U.S. election, 47% of the votes were for Don-
ald Trump, 48% of the votes were for Hilary Clinton, and the
remaining 5% were for other candidates. Suppose we take a
random sample of 30 votes cast during this election.
(a) What is the probability that exactly 13 votes are for
Trump in this sample?
(b) What is the probability that at least 12 but at most 16
votes are for Clinton in this sample?
(c) What is the probability that at least 2 votes are not for
Trump or Clinton in this sample?
(d) Calculate the expected value and the standard deviation
for the number of votes in this sample that are not for
Trump.
You can put this solution on YOUR website! 30C13(0.47)^13*0.53^17=0.1344
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30C12*0.48^12*0.52^18=0.1000
for 13 is 0.1278
for 14 is 0.1432
for 15 is 0.1410
for 16 is 0.1221
They add to 0.6431
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Neither votes do 0 and 1 and subtract from 1
0 is .95^30=0.2146
1 is 30*0.05*0.95^29=0.3389
They add to 0.5535
1-0.5535=0.4465 ANSWER
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Not votes are 0.53
mean is np=30*.53=15.9
variance is np(1-p)=15.9*.47
7.473
sqrt(7.473)=2.73=sd
