SOLUTION: Airplane 1 leaves city A for city B at the same time Airplane 2 leaves city B for city A. The distance from city A to city B is 565 miles. If Airplane 1 travels at 560 miles per ho
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Question 1070251: Airplane 1 leaves city A for city B at the same time Airplane 2 leaves city B for city A. The distance from city A to city B is 565 miles. If Airplane 1 travels at 560 miles per hour and Airplane 2 travels at 570 miles per hour, how long into their flights will the two planes pass each other?
Thank you! Answer by ikleyn(52776) (Show Source):
You can put this solution on YOUR website! .
Airplane 1 leaves city A for city B at the same time Airplane 2 leaves city B for city A. The distance from city A to city B is 565 miles.
If Airplane 1 travels at 560 miles per hour and Airplane 2 travels at 570 miles per hour, how long into their flights
will the two planes pass each other?
Thank you!
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t = = = 0.5 of an hour = 30 minutes. (*)
The numerator 565 is the distance, in miles;
the denominator 560 + 570 = 1130 is the relative speed of the two planes, or the rate of decreasing the distance between them.
The formula (*) which I used is the standard formula t = .
