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Question 1070039: In a pair of complementary angles one angle measures in (3x-40)degrees and the other is (4x+18)degrees what is the measure of the larger angle?
Found 2 solutions by Edwin McCravy, addingup:
Answer by Edwin McCravy(20056)   (Show Source):
You can put this solution on YOUR website!
"Complementary angles" means that if you add their measures,
you get 90°.
To add them you write them with a plus sign between them, like this:
(3x-40)° + (4x+18)°
Then to say that when you add them, you get 90°, you put an equal
sign after that, and then put 90° after that, like this:
(3x-40)° + (4x+18)° = 90°
Then you drop the ° marks and solve for x:
(3x-40) + (4x+18) = 90
3x - 40 + 4x + 18 = 90
7x - 22 = 90
+ 22 +22
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7x = 112
x = 112/7
x = 16
The angle (3x-40)degrees is
(3·16-40)degrees or
(48-40)degrees or
8 degrees
The angle (4x+18)degrees is
(4·16+18)degrees or
(64+18)degrees or
82 degrees
So the angles are 8° and 82°, which are complementary
because when you add them you get 90°.
The larger one is 82°.
Edwin
Answer by addingup(3677)  (Show Source):
You can put this solution on YOUR website! 3x-40+4x+18 = 90
7x-22 = 90
7x = 68
x = 9.71
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One angle:
3(9.71)-40 = negative result, not possible
The other:
4(9.71)+18 = 56.84
If this second angle is correct, the first angle would be 90-56.81 = 33.19 because the property of complementary angles is that they add up to 90 degrees.
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