SOLUTION: Two men fire at a target. The probability that Alan hits the target is ½ and the probability
that Bob does not hit the target is 1/3. Alan fires at the target first then Bob fires
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-> SOLUTION: Two men fire at a target. The probability that Alan hits the target is ½ and the probability
that Bob does not hit the target is 1/3. Alan fires at the target first then Bob fires
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Question 1069795: Two men fire at a target. The probability that Alan hits the target is ½ and the probability
that Bob does not hit the target is 1/3. Alan fires at the target first then Bob fires at the
target. Find the probability that
a) both Alan and Bob hit the target
b) only one person hits the target
c) neither hits the target Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! prob A+=1/2
prob B+=2/3
assuming independence, for both it is (1/2)(2/3)=(1/3)
for only 1 it is 1-both-0. For both it is 1/3; for neither it is (1/2)(1/3)=(1/6) That sum is 1/2 and 1-1/2=1/2.
Or, the (1/6) for A but not B and (1/3) for B but not A, and that sums to 1/2.
Neither hits is (1/6) as shown above.
