SOLUTION: Landon can climb a hill at a rate of 0.5mph slower than his rate coming down the hill. If it takes him 4 hours to climb the hill and 220 minutes to come down the hill what is his r
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-> SOLUTION: Landon can climb a hill at a rate of 0.5mph slower than his rate coming down the hill. If it takes him 4 hours to climb the hill and 220 minutes to come down the hill what is his r
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Question 1069767: Landon can climb a hill at a rate of 0.5mph slower than his rate coming down the hill. If it takes him 4 hours to climb the hill and 220 minutes to come down the hill what is his rate coming down?
Angle a has the property that twenty nine times its complement is equal to eleven times its supplement. Find the measure of angle a?
You can put this solution on YOUR website! Landon can climb a hill at a rate of 0.5mph slower than his rate coming down the hill.
If it takes him 4 hours to climb the hill and 220 minutes to come down the hill what is his rate coming down?
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let s = his rate in mph coming down the hill
then
(s-.5) = his rate climbing the hill
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Assume the distance up and down the hill are equal.
Write a distance equation; dist = time * speed
Since we are dealing in mph, change 220 min: 220/60 = 3.67 hrs
dist up = dist down
4(s-.5) = 3.667s
4s - 2 = 3.667s
4s - 3.667s = 2
.333s = 2
s = 2/.333
s = 6 mph his rate coming down the hill
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Confirm this, find the distances, should be equal
6*3.667 = 22 mi
5.5*4 = 22 mi
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Angle a has the property that twenty nine times its complement is equal to eleven times its supplement.
Find the measure of angle
29(90-A) = 11(180-A)
2610 - 29A = 1980 - 11A
2610 - 1980 = - 11A + 29A
630 = 18A
A = 630/18
A = 35 degrees
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See if that checks out
29(90-35) = 11(180-35)
29(55) = 11(145)
1595 = 1595
