SOLUTION: Question: A basketball player has a 50% chance of making each free throw. What is the probability that the player makes at least two out of six free throws? My Attempt: I first

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Question 1069711: Question: A basketball player has a 50% chance of making each free throw. What is the probability that the player makes at least two out of six free throws?
My Attempt: I first found (1/2)^6 , because we have 6 "spots" or free throws.
Since finding 2,4,5,6 all work, I found in how many combinations can he make each of those events...15+40+15+6+1=77... My answer then would be 77/64. But the probability has to be less than 1....Where might have I went wrong?
Thanks in Advance!

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
P%28X%29=C%286%2CX%29%2A%281%2F2%29%5EX%2A%281%2F2%29%5E%286-X%29
P%28X%29=C%286%2CX%29%281%2F2%29%5E6
P%28X%29=C%286%2CX%29%2F64
So then,
P%280%29=1%2F64
P%281%29=6%2F64
P%282%29=15%2F64
P%283%29=20%2F64<--- You had 40, that was your mistake.
P%284%29=15%2F64
P%285%29=6%2F64
P%286%29=1%2F64
At least two means two through six,
P=%2815%2B20%2B15%2B6%2B1%29%2F64
P=57%2F64