SOLUTION: X an Y are two stations 500 km apart. A train starts form X and moves towards Y at 20 km/hr. Another rain starts from Y at the same time and moves towards X at 30 km/hr. How far fr

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Question 1069683: X an Y are two stations 500 km apart. A train starts form X and moves towards Y at 20 km/hr. Another rain starts from Y at the same time and moves towards X at 30 km/hr. How far from X will they cross each other:
Found 2 solutions by ikleyn, MathTherapy:
Answer by ikleyn(52802) About Me  (Show Source):
You can put this solution on YOUR website!
.
Time they travel before they cross each other is  500%2F%2820%2B30%29 = 10 hours.


During 10 hours the first train covers  10*20 = 200 km.


Answer.  200 km.

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The tutor "MathTherapy" wrote his own solution.
Probably, he tried to prove that I made a mistake in my solution.

But instead, he made a mistake in his own solution.

Below I re-wrote his solution with my correction. It gives the same result/answer as my original solution.
------------------------------

With D being the distance from X where they cross, we get the following TIME equation: D%2F20+=+%28500+-+D%29%2F30
30D = 20(500 - D) ------- Cross-multiplying
30D = 10,000 - 20D
30D + 20D = 10,000
50D = 10,000
D, or distance form X where they cross = highlight_green%28matrix%281%2C4%2C+%2210%2C000%22%2F50%2C+or%2C+200%2C+km%29%29


Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
X an Y are two stations 500 km apart. A train starts form X and moves towards Y at 20 km/hr. Another rain starts from Y at the same time and moves towards X at 30 km/hr. How far from X will they cross each other:
With D being the distance from X where they cross, we get the following TIME equation: D%2F20+=+%28500+-+D%29%2F30
30D = 20(500 - D) ------- Cross-multiplying
30D = 10,000 - 20D
30D + 20D = 10,000
50D = 10,000
D, or distance form X where they cross = highlight_green%28matrix%281%2C4%2C+%2210%2C000%22%2F50%2C+or%2C+200%2C+km%29%29