SOLUTION: I am supposed to solve this question using variables. I have to write it in an outline format, so it is confusing to me because I can solve it without using variables. Here is the
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Question 1069680: I am supposed to solve this question using variables. I have to write it in an outline format, so it is confusing to me because I can solve it without using variables. Here is the problem:
In order to receive an A in a college course it is necessary to obtain an average of 90% correct on three 1-hour exams of 100 points each and on one final exam of 200 points. If a student scores 82, 88, and 91 on the 1-hour exams, what is the minimum score that the person can receive on the final exam and still earn an A?
So for the three 1-hour exams, the total possible points are 300 and the student got 261/300 = 87%. So for the final exam of 200 points, they would need to get a minimum of 189/200 = 95%, to bring the total to 450/500 = 90%. Now I just don't know how to put all that into a variable form to make it an "x+y" type problem :-/ Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website! The final exam is equivalent to two regular 100-point exams.
That means, 3 regular + 2 regular = 5 regular, examinations.
Emphasis for grading is on the average for the three regular plus one final tests. Target minimum percent average for grade A is 90%.
This should be the equation to solve; and understand you can say in place of the in the numerator. The variable , x, is the score on the final exam. Remember, this final exam counts as TWO regular tests.
Same as ;
Just SOLVE for x.
That will be the minimum score needed to get average 90% on all the tests plus final.
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