SOLUTION: sally left point A at 6:00 am and reached point B at 10 am. Jane left one hour later and arrived at point B at the same time as sally. Jane traveled two miles an hour faster than s

Algebra ->  Rational-functions -> SOLUTION: sally left point A at 6:00 am and reached point B at 10 am. Jane left one hour later and arrived at point B at the same time as sally. Jane traveled two miles an hour faster than s      Log On


   

Question 1069651: sally left point A at 6:00 am and reached point B at 10 am. Jane left one hour later and arrived at point B at the same time as sally. Jane traveled two miles an hour faster than sally.
what was sallys rate of travel?
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Travel time for Sally was 4 hours.
Travel time for Jane was 3 hours.

Both went the same distance.
r%2A4=%28r%2B2%29%2A3

4r=3r%2B6

r=6------Sally's rate