SOLUTION: gerry left at 4:00 pm. traveling at 55 mph. Joe left one hour later and passed gerry at 9:00 pm. How fast was joe traveling?

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: gerry left at 4:00 pm. traveling at 55 mph. Joe left one hour later and passed gerry at 9:00 pm. How fast was joe traveling?      Log On


   



Question 1069623: gerry left at 4:00 pm. traveling at 55 mph. Joe left one hour later and passed gerry at 9:00 pm. How fast was joe traveling?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Joe left 1 hr later at 5:00 PM
During that 1 hr, Gerry traveled
+d%5B1%5D+=+55%2A1+
+d%5B1%5D+=+55+ mi
Let +s+ = Joe's speed in mi/hr
------------------------------------
From 5:00 to 9:00 PM is +4+ hrs
During that time, Joe traveled
+d+=+s%2A4+
------------------------------------
Equation for Gerry:
(1) +d+-+d%5B1%5D+=+55%2A4+
Equation for Joe:
(2) +d+=+s%2A4+
-------------------------------
(1) +d+-+55+=+220+
(1) +d+=+275+
Substitute (1) into (2)
(2) +275+=+4s+
(2) +s+=+68.75+
Joe was traveling 68.75 mi/hr
------------------------------
check:
In 5 hrs, ( 4 + 1 hr ) Gerry traveled
+d+=+55%2A5+
+d+=+275+ mi
--------------------
Check my math and get
another opinion if you need to.