SOLUTION: 2 x y^3 + 5 y ^2 -4 y para x=2 y=2

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Question 1069608: 2 x y^3 + 5 y ^2 -4 y para x=2 y=2
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
2 x y^3 + 5 y ^2 -4 y para x=2 y=2
2 x y^3 + 5 y ^2 -4 y   para x=2   y=2


You wish to evaluate xy%5E3%2B5y%5E2-4y for x=2 and y=2.

Just substitute for x and y as assigned and compute the value for the expression.
2%2A2%5E3%2B5%2A2%5E2-4%2A2, compute this.