SOLUTION: Use a system of equations to solve this problem.
A chemist currently has two solutions of sodium chloride. One solution has a 5% concentration and the other has a 25% concentrat
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A chemist currently has two solutions of sodium chloride. One solution has a 5% concentration and the other has a 25% concentrat
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Question 1069565: Use a system of equations to solve this problem.
A chemist currently has two solutions of sodium chloride. One solution has a 5% concentration and the other has a 25% concentration. The chemist needs to make 10 L of a 10% sodium chloride solution.
Let x = the amount of 5% solution.
Let y = the amount of 25% solution.
How much of each solution does the chemist need to make?
Enter your answers, as decimals, in the boxes. Found 2 solutions by josgarithmetic, MathTherapy:Answer by josgarithmetic(39617) (Show Source):
If as w/w, then you need to know or use or refer to
5% 1.034 g/ml
10% 1.0707 g/ml
24% 1.1804 g/ml
26% 1.1972 g/ml
Middle of 24 and 26 percents should give 1.1888 g/ml for 25% solution.
Refered to online, http://chemistry.mdma.ch/hiveboard/rhodium/pdf/chemical-data/prop_aq.pdf
You can put this solution on YOUR website! Use a system of equations to solve this problem.
A chemist currently has two solutions of sodium chloride. One solution has a 5% concentration and the other has a 25% concentration. The chemist needs to make 10 L of a 10% sodium chloride solution.
Let x = the amount of 5% solution.
Let y = the amount of 25% solution.
How much of each solution does the chemist need to make?
Enter your answers, as decimals, in the boxes.
The system of equations you need is:
Solve to get "x", or the amount of 5% solution to be mixed
Solve to get "y," or the amount of 25% solution.
**Note that the amount of the 5% solution will be 5 times the amount of the 25% solution.
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