SOLUTION: {{{12^(x-2)=20}}} How do you find x? I did {{{ (x-2)log12=20}}} {{{ x-2= (20/log12)}}} {{{ x= (20/log12)+2}}} x=20.5326816

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: {{{12^(x-2)=20}}} How do you find x? I did {{{ (x-2)log12=20}}} {{{ x-2= (20/log12)}}} {{{ x= (20/log12)+2}}} x=20.5326816      Log On


   

Question 1069399: 12%5E%28x-2%29=20
How do you find x?
I did
+%28x-2%29log12=20
+x-2=+%2820%2Flog12%29
+x=+%2820%2Flog12%29%2B2
x=20.5326816
Found 3 solutions by josgarithmetic, ikleyn, jorel1380:
Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
Take logarithm of BOTH SIDES of the equation.

Answer by ikleyn(52817) About Me  (Show Source):
You can put this solution on YOUR website!
.
On logarithms, see the lessons
    - WHAT IS the logarithm
    - Properties of the logarithm
    - Change of Base Formula for logarithms
    - Solving logarithmic equations
    - Using logarithms to solve real world problems
in this site.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Logarithms".


Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
First off, you have to take the logarithm of both sides:
12^(x-2)=20
log 12^(x-2)=log 20
(x-2)log 12=log 20
x-2=log 20/log 12
x=(log 20/log 12)+2=3.20557135368 ☺☺☺☺