SOLUTION: Suppose Z is a standard normal random variable. If P(-z < Z < z) = 0.5588, find z. Find P( -2.46 < Z < -0.16) Some did it but wasn't right Please help Thank you so much

Algebra ->  Probability-and-statistics -> SOLUTION: Suppose Z is a standard normal random variable. If P(-z < Z < z) = 0.5588, find z. Find P( -2.46 < Z < -0.16) Some did it but wasn't right Please help Thank you so much      Log On


   



Question 1069398: Suppose Z is a standard normal random variable.
If P(-z < Z < z) = 0.5588, find z.
Find P( -2.46 < Z < -0.16)
Some did it but wasn't right
Please help
Thank you so much

Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!
Suppose Z is a standard normal random variable.
If P(-z < Z < z) = 0.5588, find z.
Find P( -2.46 < Z < -0.16)
Some did it but wasn't right
Please help
Thank you so much
As P(- z < Z < z) = 0.5588, .5588 is the center interval beneath the bell curve
Therefore, to the left of the P(Z), probability = 1 - .5588, or .4412
This probability represents the TOTAL probabilities of the left and right tails
We now take the AVERAGE of this probability to get matrix%281%2C3%2C+.4412%2F2%2C+%22=%22%2C+.2206%29
Using a calculator, excel, or other applications, you'll find that the z-score that represents a probability (to the left of the curve) of .2206 is: - 0.77,
which means that: . This is close enough.