SOLUTION: A jar of 45 coins consists only of nickels, dimes, and quarters, with a face value of $5.90. The numbers of nickels and dimes together exceed the number of quarters by 19. How many
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Question 1069343: A jar of 45 coins consists only of nickels, dimes, and quarters, with a face value of $5.90. The numbers of nickels and dimes together exceed the number of quarters by 19. How many quarters are in the jar? Answer by ikleyn(52847) (Show Source):
You can put this solution on YOUR website! .
A jar of 45 coins consists only of nickels, dimes, and quarters, with a face value of $5.90.
The numbers of nickels and dimes together exceed the number of quarters by 19. How many quarters are in the jar?
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N + D + Q = 45, (1)
N + D - Q = 19. (2)
Subtract eq(2) from eq(1) (both sides). You will get
2Q = 45 - 19 = 26 ---> Q = = 13.
Answer. 13 quarters.
The info about "face value" is excessive, unnecessary and serves for only one goal: to confuse the reader.
