SOLUTION: Find four consecutive integers such that four times the third is 83 more than the first

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Question 1069332: Find four consecutive integers such that four times the third is 83 more than the first
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
x, x+1,x+2,x+3
4(x+2)=x+83
4x+8=x+83
3x=75
x=25
the integers are 25,26,27,28
and 4*27=108 and that is 83 more than 25.