SOLUTION: A bag has 2 yellow, 7 red, and 1 green marble. What is the probability of picking a red marble, replacing it, and then picking another red marble?
1/25
1/50
49/100
7/100
T
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-> SOLUTION: A bag has 2 yellow, 7 red, and 1 green marble. What is the probability of picking a red marble, replacing it, and then picking another red marble?
1/25
1/50
49/100
7/100
T
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Question 1069292: A bag has 2 yellow, 7 red, and 1 green marble. What is the probability of picking a red marble, replacing it, and then picking another red marble?
1/25
1/50
49/100
7/100
Thanks so much Answer by geo_freak(10) (Show Source):
You can put this solution on YOUR website! Total # of marbles: 10
# of red marbles: 7
Probability of choosing a red marble out of 10 marbles: 7/10
Then in the second round, you replace that marble so you still have a total of 10 marbles and 7 of them will still be red: 7/10
Multiply...
7/10 x 7/10 = 49/100
PROBABILITY: 49/100 (or 49%)
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