Question 1069236: The ocean contains around 0.15 milligrams of gold for every ton of sea water. Gold is currently worth $36 per gram of gold. The density of sea water is 1.03 g/mL. Use this information to determine how many liters of sea water would have to be processed in order to obtain $10.00 worth of gold. Give your answer to two significant digits, using proper scientific notation.
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! The ocean contains around 0.15 milligrams of gold for every ton of sea water. Gold is currently worth $36 per gram of gold. The density of sea water is 1.03 g/mL. Use this information to determine how many liters of sea water would have to be processed in order to obtain $10.00 worth of gold. Give your answer to two significant digits, using proper scientific notation.
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Using metric tons (1000 kgs):
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$10/$36/gram --> 5/18 grams = 2500/9 milligrams.
(2500/9) mgrams/0.15 mgrams/tonne = 2500/1.35 tonnes = 50000/27 tonnes = 5e7/27 kg = 5e10/27 grams to get $10
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5e10/27 grams /(1.03 gm/ml) = 5e10/(27*1.03) ml of water = 5e7/27.81 liters
=~ 0.18e7 liters
= 1.8e6 liters
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For US tons, multiply by 2204/2000
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