SOLUTION: Two​ joggers, one averaging 5 mph and one averaging 4 ​mph, start from a designated initial point. The slower jogger arrives at the end of the run 35 minute

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Question 1068895: Two​ joggers, one averaging 5

mph and one averaging 4

​mph, start from a designated initial point. The slower jogger arrives at the end of the run 35

minutes after the other jogger. Find the distance of the run.
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
                speed        time          distance

Fast             5           t               d

Slow             4           t+35/60         d


35%2F60=5%2A7%2F%285%2A12%29=7%2F12

-
system%285t=d%2C4%28t%2B7%2F12%29=d%29

t=d%2F5
-
4t%2B7%2F3=d
4d%2F5%2B7%2F3=d
3%2A5%284d%2F5%2B7%2F3%29=3%2A5%2Ad
12d%2B35=15d
35=3d
d=35%2F3
highlight%28d=11%262%2F3%29

Answer by ikleyn(52851) About Me  (Show Source):
You can put this solution on YOUR website!
.
Two​ joggers, one averaging 5 mph and one averaging 4 ​mph, start from a designated initial point.
The slower jogger arrives at the end of the run 35 minutes after the other jogger. Find the distance of the run.
~~~~~~~~~~~~~~~~~~~~~~ 

D%2F4+-+D%2F5 = 35%2F60    (the difference of jogging times is 35 minutes)

Multiply both sides by 60. You will get

15D - 12D = 35,

3D = 35  --->  D = 35%2F3 = 112%2F3 mile.

Answer. The distance is 112%2F3 miles.