SOLUTION: A mass of gas occupies a volume of 4.70 liters at a pressure of 1.30 atm and a temperature of 300 K. It is compressed adiabatically to a volume of 1.50 liter. Determine the final p

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: A mass of gas occupies a volume of 4.70 liters at a pressure of 1.30 atm and a temperature of 300 K. It is compressed adiabatically to a volume of 1.50 liter. Determine the final p      Log On


   

Question 1068800: A mass of gas occupies a volume of 4.70 liters at a pressure of 1.30 atm and a temperature of 300 K. It is compressed adiabatically to a volume of 1.50 liter. Determine the final pressure (in atmospheres) of the gas. (The specific heat ratio = 1.5)
Answer by trsomas23@gmail.com(17) About Me  (Show Source):
You can put this solution on YOUR website!
P1+V1%5Egamma+=+P2+V2%5Egamma
1.30 x 4.70%5E1.5 = P2 x 1.50%5E1.5
P2 = 1.30 x %284.70%2F1.50%29%5E1.5
= 7.21 atm
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