SOLUTION: solve by factoring a) x^3-2x^2-5x+6=0 b) 3x^3+2X^2-8x+3=0 solve 2x^4-x^3=7x^2-9x+3

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: solve by factoring a) x^3-2x^2-5x+6=0 b) 3x^3+2X^2-8x+3=0 solve 2x^4-x^3=7x^2-9x+3      Log On


   

Question 1068781: solve by factoring
a) x^3-2x^2-5x+6=0
b) 3x^3+2X^2-8x+3=0
solve 2x^4-x^3=7x^2-9x+3
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
1/1===-2===-5===6
=1====-1===-6===0
(x-1)(x^2-x-6)=0;(x-1)(x-3)(x+2)=0 roots are 1,3,-2
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2Cx%5E3-2x%5E2-5x%2B6%29
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1/3===2===-8===3
=3===5===-3===0
(x-1)(3x^2+5x-3)=0; roots are 1,(1/6)(-5+/- sqrt(61))
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C3x%5E3%2B2x%5E2-8x%2B3%29
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