Question 1068524: Josh launches a rocket straight up into the air. The table below gives the height H (t) of the rocket (in meters) at a few times t (in seconds) during its flight.
Time t Height H (t)
(seconds) (meters)
0, 0
2.2, 110
6.6, 198
8.8, 44
13.2, 0
Because the chart is not posting correctly above, below it the same chart with columns separate.
Time t
(seconds)
0
2.2
6.6
8.8
13.2
Height H (t)
(meters)
0
110
198
44
0
a). Find the average rate of change for the height from 0 seconds to 6.6 seconds.
_______ meters per second.
b). Find the average rate of change for the height from 8.8 seconds to 13.2 seconds.
_______ meters per second.
Answer by Fombitz(32388)   (Show Source):
You can put this solution on YOUR website! To find the average rate of change between two times, find the value at each time,
(0,0)
(6.6,198)
Then find the difference in the values divided by the difference in times,
 
Do the same for the other two data points.
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