SOLUTION: Distance between A and B railway stations are 300km. Train X takes 12 hours to reach B from A and return back to A. Also the train stops in B for 2 hours. After 10hours train

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Question 1068432: Distance between A and B railway stations are 300km. Train X takes 12 hours to reach B from A and return back to A. Also the train stops in B for 2 hours. After 10hours train Y departed from A to B with train X's' speed.
What is the distance traveled by train Y when meeting both trains?
What is the time when meeting both trains If train x departed from A at 8.00 A.M?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+12+-+2+=+10+ hrs is the time for a
round trip by X
+10%2F2+=+5+ hrs is the one-way time for X
+300%2F5+=+60+ km/hr is speed for X
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In +10+ hrs, X has been traveling for +10+-+2+=+8+
hrs, so X is +60%2A%28+8-5+%29+=180+ km from B
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So now Y is at A and X is +300+-+180+=+120+ km
from Y and they are headed toward each other at +60+ km/hr
----------------------------
Think of this as one of them standing still and the other moving
at the sum of their speeds
+120+=+%28+60+%2B+60+%29%2At+
+120+=+120t+
+t+=+1+ hr
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In +1+ hr, Y travels +60%2A1+=+60+ mi
and meets X
-----------------
If X departed at 8:00 AM, then +10+%2B+1+=+11+ hrs later is
7:00 PM when trains meet ( 1 hr less than 12 hrs later )
-----------------------------------
DEFINITELY get another opinion on this.
I could easily mess this up.